Now we are looking on the crossword clue: In short supply.
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Possible Answers: SPARSE.
Random information on “SPARSE”:
SPARSE contains TALLY, the class of unary languages, since these have at most one string of any one length. Although not all languages in P/poly are sparse, there is a polynomial-time Turing reduction from any language in P/poly to a sparse language.[1] Fortune showed in 1979 that if any sparse language is co-NP-complete, then P = NP;[2] Mahaney used this to show in 1982 that if any sparse language is NP-complete, then P = NP (this is Mahaney’s theorem).[3] A simpler proof of this based on left-sets was given by Ogihara and Osamu in 1991.[4] E ≠ NE if and only if there exist sparse languages in NP that are not in P.[5] In 1999, Jin-Yi Cai and D. Sivakumar, building on work by Ogihara, showed that if there exists a sparse P-complete problem, then L = P.[6]
Taken from Wikipedia